What is the complete factorization of $x^2-8x+16$ ?

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Answer 1 · 2017-01-09T20:23:34

To completely factor this we need to "play" with multiples of $16$ : (1x16, 2x8, 4x4, 8x2, 16x1).

This gives:

$(x - 4)(x - 4)$ or $(x - 4)^2$

What is the complete factorization of x^2-8x+16x^2-8x+16?