# What is the density, in g/L, of CO_2 gas at 27°C and 0.50 atm pressure?

Apr 14, 2017

We rearrange the Ideal Gas Equation............and get $\rho \cong 0.9 \cdot g \cdot {L}^{-} 1$

#### Explanation:

$P V = n R T$, which equation is this?

So $\frac{P V}{R T} = n = \text{Mass"/"Molar Mass}$

And thus, ("Molar Mass"xxP)/(RT)="Mass"/V

But $\text{Mass"/V=rho"(density)}$

And thus $\rho = \frac{\text{Molar mass} \times P}{R T}$

And now we plug in the values.........

rho=(44.01*g*mol^-1xx0.50*atm)/(0.0821*(L*atm)/(K*mol)xx300*K)=??*g*L^-1