# What is the density of a bowling ball with a mass of #3.0# #kg# and a volume of #0.0050# #m^3#?

##### 1 Answer

#### Explanation:

In order to find the **density** of the bowling ball, **one unit of volume** of this bowling ball would have.

Notice that the problem provides you with the volume of the bowling ball expressed *cubic meters*,

Now, you know that a volume of *conversion factor* to figure the mass of

#1 color(red)(cancel(color(black)("m"^3))) * "3.0 kg"/(0.0050 color(red)(cancel(color(black)("m"^3)))) = "600 kg"#

So, you know that one unit of volume has a mass of

#color(darkgreen)(ul(color(black)(rho = 6.0 * 10^2"kg m"^(-3))))#

The answer is rounded to two **sig figs**.