What is the density of #NO_2# gas at .970 atm and 35°C?

1 Answer

Answer:

#"1.77 g/L"#

Explanation:

#PV = nRT#

#P# is the pressure in #"atm"#.
#V# is volume in #"L"#.
#n# is mols of ideal gas.
#R# is the universal gas constant.
#T# is temperature in #"K"#.

#n/V = P/(RT)#
#= ("0.970 atm") / (["0.08205746 L"cdot" atm /K"cdot" mol"] xx ["35 + 273 K"])#

#=# #"0.0383798 mol/L"#

Molar mass multiplied by n/V = density:

#("46.0056 g NO"_2)/"mol" xx "0.0383798 mol"/"L" = "1.77 g/L"#