# What is the density of #NO_2# gas at .970 atm and 35°C?

##### 1 Answer

Jan 18, 2018

#### Answer:

#### Explanation:

#PV = nRT#

#P# is the pressure in#"atm"# .

#V# is volume in#"L"# .

#n# is mols of ideal gas.

#R# is the universal gas constant.

#T# is temperature in#"K"# .

#n/V = P/(RT)#

#= ("0.970 atm") / (["0.08205746 L"cdot" atm /K"cdot" mol"] xx ["35 + 273 K"])#

#=# #"0.0383798 mol/L"#

Molar mass multiplied by n/V = density:

#("46.0056 g NO"_2)/"mol" xx "0.0383798 mol"/"L" = "1.77 g/L"#