What is the density of #NO_2# gas at .970 atm and 35°C?
1 Answer
Jan 18, 2018
Explanation:
#PV = nRT#
#P# is the pressure in#"atm"# .
#V# is volume in#"L"# .
#n# is mols of ideal gas.
#R# is the universal gas constant.
#T# is temperature in#"K"# .
#n/V = P/(RT)#
#= ("0.970 atm") / (["0.08205746 L"cdot" atm /K"cdot" mol"] xx ["35 + 273 K"])#
#=# #"0.0383798 mol/L"#
Molar mass multiplied by n/V = density:
#("46.0056 g NO"_2)/"mol" xx "0.0383798 mol"/"L" = "1.77 g/L"#
