# What is the derivative of -4/x^2?

Jan 20, 2016

$\frac{8}{x} ^ 3$

#### Explanation:

A standard rule states that $\frac{d}{\mathrm{dx}} a {x}^{n} = n a {x}^{n - 1}$.

So we rewrite the given function in polynomial form using the laws of exponents, then apply this rule to obtain.

$\frac{d}{\mathrm{dx}} \left(- \frac{4}{x} ^ 2\right) = \frac{d}{\mathrm{dx}} \left(- 4 {x}^{- 2}\right)$

$= 8 {x}^{- 3}$

$= \frac{8}{x} ^ 3$