Question

What is the derivative of `f(t) = (e^(t^2)-e^t, 2t^2-4t )`?

Answer 1

`f'(t)=(4t-4)/(2te^(t^2)-e^t)`

Explanation:

`x'(t)=2te^(t^2)-e^t`
`y'(t)=4t-4`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(4t-4)/(2te^(t^2)-e^t)`