What is the derivative of #f(t) = (t^2-lnt, t^2-sin^2t ) #?
1 Answer
Mar 21, 2017
Explanation:
differentiate using.
#• dy/dx=dy/dt-:dx/dt#
#x=t^2-lntrArrdx/dt=2t-1/t#
#y=t^2-sin^2t=t^2-(sint)^2#
#rArrdy/dt=2t-2sintcost=2t-sin2t#
#rArrdy/dx=(2t-sin2t)/(2t-1/t)#
