What is the derivative of f(t) = (t^3e^(1-t) , tan^2t ) ?

1 Answer
Jan 10, 2018

(3t^2 e^(1-t) -t^3 e^(1-t))i +2tant sec^2 t j Or,
f'(t)= ((3t^2 -t^3)e^(1-t), 2tan t sec^2 t)

Explanation:

Given f(t) is t^3 e^(1-t) i + tan^2 t j

Its derivative f'(t) would be (3t^2 e^(1-t) -t^3 e^(1-t))i +2tant sec^2 t j. This can also be expressed as

f'(t)= ((3t^2 -t^3)e^(1-t), 2tan t sec^2 t)