What is the derivative of f(x) = x/(1-ln(x-1))?

1 Answer
Apr 10, 2015

f'(x)=(2x-1-(x-1)ln(x-1))/((x-1)[(1-ln(x-1)]^2

The complete solution is here

f(x)=x/(1-ln(x-1)

f'(x)=(1(1-ln(x-1))-x(0-1/(x-1)))/([(1-ln(x-1)]^2

f'(x)=((x-1)[1-ln(x-1)]+x)/((x-1)[(1-ln(x-1)]^2

f'(x)=(x-1-(x-1)ln(x-1)+x)/((x-1)[(1-ln(x-1)]^2

f'(x)=(2x-1-(x-1)ln(x-1))/((x-1)[(1-ln(x-1)]^2