What is the derivative of # ln(sin^2x)#? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer AltairSafir May 11, 2018 Use chain rule #f(x)=h(g(x))# #f'(x)=h'(g(x)) g'(x)# Explanation: #ln(sin^2(x))# #(ln(sin^2(x)))'=# #=1/(sin^2(x))*(sin^2(x))'=# #=1/(sin^2(x))2*(sin(x))*(sin(x))'=# #=2/(sin(x))*(cos(x))=2/tan(x)=2 cot(x)# Answer link Related questions What is the derivative of #-sin(x)#? What is the derivative of #sin(2x)#? How do I find the derivative of #y=sin(2x) - 2sin(x)#? How do you find the second derivative of #y=2sin3x-5sin6x#? How do you compute #d/dx 3sinh(3/x)#? How do you find the derivative #y=xsinx + cosx#? What is the derivative of #sin(x^2y^2)#? What is #f'(-pi/3)# when you are given #f(x)=sin^7(x)#? How do you find the fist and second derivative of #pi*sin(pix)#? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 3860 views around the world You can reuse this answer Creative Commons License