Question

What is the derivative of `ln( t /t^2)`?

Answer 1

`-1/t`

Explanation:

Using the chain rule together with other standard rules of differentiation and laws of exponents and logs, we get:

`d/dtln(t/t^2)=d/dtln(1/t)`

`=1/(1/t)*d/dt(1/t)`

`=t*(-t^(-2))`

`=-1/t`