What is the derivative of this function #sin x^(1/2)#?
1 Answer
Sep 7, 2016
Explanation:
differentiate using the
#color(blue)"chain rule"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(dy/dx=(dy)/(du)xx(du)/(dx))color(white)(a/a)|)))....(A)# let
#u=x^(1/2)rArr(du)/(dx)=1/2x^(-1/2)# and
#y=sin(u)rArr(dy)/(du)=cos(u)# substitute these values into (A) changing u into terms of x
#rArrdy/dx=cos(u)xx1/2x^(-1/2)=cos(x^(1/2))/(2x^(1/2)#