# What is the derivative of this function sin(x^3+1)?

$\frac{d}{\mathrm{dx}} \sin \left({x}^{3} + 1\right) = 3 x \cos \left({x}^{3} + 1\right)$
$\frac{d}{\mathrm{dx}} \sin \left({x}^{3} + 1\right) = \cos \left({x}^{3} + 1\right) . \left(3 x\right)$
$\therefore \frac{d}{\mathrm{dx}} \sin \left({x}^{3} + 1\right) = 3 x \cos \left({x}^{3} + 1\right)$