Question

What is the derivative of `y=1/(4-x^2)`?

Answer 1

`dy/dx = (2x)/(4-x^2)^2`

Explanation:

`y =1/(4-x^2) = (4-x^2)^-1.`

This can easily be differentiated using the chain rule

`dy/dx = -1(4-x^2)^-2(-2x) = (2x)/(4-x^2)^2`