What is the derivative of y = ln(sin^2(theta))? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer The_tutor Oct 9, 2016 Cot^2theta Explanation: Using the chain rule we have: F(x)'= f'(g(x))*g'(x) y'=ln'(sin^2(theta))*(cos^2(theta)) 1/sin^2theta *Cos^2theta Cot^2theta Answer link Related questions What is the derivative of -sin(x)? What is the derivative of sin(2x)? How do I find the derivative of y=sin(2x) - 2sin(x)? How do you find the second derivative of y=2sin3x-5sin6x? How do you compute d/dx 3sinh(3/x)? How do you find the derivative y=xsinx + cosx? What is the derivative of sin(x^2y^2)? What is f'(-pi/3) when you are given f(x)=sin^7(x)? How do you find the fist and second derivative of pi*sin(pix)? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 3021 views around the world You can reuse this answer Creative Commons License