What is the distance between # (0, 4, –2) # and #(–1, 4, –2) #?
1 Answer
May 6, 2016
Explanation:
The distance between
#d = sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2#
#sqrt((-1-0)^2+(4-4)^2+(-2-(-2))^2))#
#= sqrt(1+0+0)#
#= sqrt(1) = 1#
Alternatively, simply notice that the