What is the distance between # (0, 4, –2)# and #(–1, 4, –2) #?

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Answer 1 · 2018-06-14T05:36:06

#d = 1#

The formula for the distance for 3-dimensional coordinates is similar or 2-dimensional; it is: #d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2)#

We have the two coordinates, so we can plug in the values for #x#, #y#, and #z#:
#d = sqrt((-1-0)^2 + (4-4)^2 + (-2-(-2))^2)#

Now we simplify:
#d = sqrt((-1)^2 + (0)^2 + (-2+2)^2)#

#d = sqrt(1 + 0)#

#d = sqrt(1)#

#d = 1#

Hope this helps!