What is the distance between #(0,5)# and #(4,2)#?
1 Answer
May 1, 2016
Explanation:
The distance
#d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)#
#=sqrt((4-0)^2+(2-5)^2)#
#=sqrt(4^2+(-3)^2)#
#=sqrt(16+9)#
#=sqrt(25)#
#=5#
