# What is the distance between  (1, –2, 0)  and (0, 4, –2) ?

##### 1 Answer

The distance is $\sqrt{41}$

#### Explanation:

The distance between points in 3 dimensional space is given by

$d = \sqrt{{\left({x}_{A} - {x}_{B}\right)}^{2} + {\left({y}_{A} - {y}_{B}\right)}^{2} + {\left({z}_{A} - {z}_{B}\right)}^{2}} = \sqrt{{\left(1 - 0\right)}^{2} + {\left(- 2 - 4\right)}^{2} + {\left(0 + 2\right)}^{2}} = \sqrt{1 + 36 + 4} = \sqrt{41}$