What is the distance between $(1, –2, 0)$ and $(0, 4, –2)$ ?

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Answer 1 · 2016-02-05T00:11:40

The distance is $sqrt41$

The distance between points in 3 dimensional space is given by

$d=sqrt[(x_A-x_B)^2+(y_A-y_B)^2+(z_A-z_B)^2]=sqrt[(1-0)^2+(-2-4)^2+(0+2)^2]=sqrt[1+36+4]=sqrt41$

What is the distance between (1, –2, 0) (1, –2, 0) and (0, 4, –2) (0, 4, –2) ?