# What is the distance between (1, -3)  and (-2, 4) ?

Jan 27, 2016

$\sqrt{58}$

#### Explanation:

$\left(1 , - 3\right)$ and $\left(- 2 , 4\right)$

So the distance formula is:

$d = \sqrt{{\left(y 2 - y 1\right)}^{2} + {\left(x 2 - x 1\right)}^{2}}$

Plug in the $x$ and $y$ values.
It should look like this:

$d = \sqrt{{\left(4 + 3\right)}^{2} + {\left(- 2 - 1\right)}^{2}}$

Solve.
First, work in the parenthesis.
$\sqrt{{\left(7\right)}^{2} + {\left(- 3\right)}^{2}}$
Then, do the rest.
$\sqrt{49 + 9}$
$\sqrt{58}$
:D