What is the distance between #(-1,7)# and #(2,12)#?

1 Answer
Apr 22, 2016

Answer:

#d=sqrt(34)approx5.83#

Explanation:

The distance formula is this: #d=sqrt((y_2-y_1)^2+(x_2-x_1)^2)#, where #(x_1,y_1)# are the coordinates of the first point, #(x_2,y_2)# are the coordinate of the second point, and #d# is the distance between the two points.

Let's say #(-1,7)# is the first point, and #(2,12#) is the second point Note that it doesn't matter which one we call the first or second point

#d=sqrt((12-7)^2+(2-(-1))^2)#
#d=sqrt(5^2+3^2)#
#d=sqrt(25+9)#
#d=sqrt(34)approx5.83#