# What is the distance between (10, 8) and (-10, 6) ?

Jan 21, 2016

2sqrt(101

#### Explanation:

The distance formula for Cartesian coordinates is

d=sqrt((x_2-x_1)^2+(y_2-y_1)^2
Where ${x}_{1} , {y}_{1}$, and${x}_{2} , {y}_{2}$ are the Cartesian coordinates of two points respectively.
Let $\left({x}_{1} , {y}_{1}\right)$ represent $\left(10 , 8\right)$ and $\left({x}_{2} , {y}_{2}\right)$ represent $\left(- 10.6\right)$.
implies d=sqrt((-10-10)^2+(6-8)^2
implies d=sqrt((-20)^2+(-2)^2
implies d=sqrt(400+4
implies d=2sqrt(100+1
implies d=2sqrt(101

Hence the distance between the given points is $2 \sqrt{101}$ units.