# What is the distance between (-12,1,3) and (-6,2,1)?

Feb 7, 2017

The distance is $= \sqrt{41} = 6.4$

#### Explanation:

The distance between 2 points $\left({x}_{1} , {y}_{1} , {z}_{1}\right)$and $\left({x}_{2} , {y}_{2} , {z}_{2}\right)$, is

$d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$

So,

$d = \sqrt{{\left(- 6 + 12\right)}^{2} + {\left(2 - 1\right)}^{2} + {\left(1 - 3\right)}^{2}}$

$= \sqrt{36 + 1 + 4}$

$= \sqrt{41} = 6.4$