What is the distance between (13,23,-1)(13,23,−1) and (-3,17,2)(−3,17,2)?
1 Answer
Jan 12, 2016
d = sqrt301 ≈ 17.35 d=√301≈17.35
Explanation:
To calculate the distance between the 2 points use the three dimensional form of the distance formula :
d = sqrt((x_2 - x_1 )^2 + (y_2 - y_1 )^2 + (z_2 - z_1 )^2 d=√(x2−x1)2+(y2−y1)2+(z2−z1)2
where (x_1 , y_1 , z_1 ) , (x_2 , y_2 , z_2 ) where(x1,y1,z1),(x2,y2,z2) are 2 points.In this question let
(x_1 , y_! , z_1 ) = (13 , 23 , - 1 ) (x1,y!,z1)=(13,23,−1) and
(x_2 , y_2 , z_2 ) = (- 3 ,17 , 2 ) (x2,y2,z2)=(−3,17,2)
substitute into the formula :
d = sqrt ( (- 3 - 13 )^2 + (17 - 23 )^2 + (2 - (-1))^2) d=√(−3−13)2+(17−23)2+(2−(−1))2
= sqrt((- 16 )^2 + (-6)^2 + 3^2 =√(−16)2+(−6)2+32
rArr d = sqrt(256 + 36 + 9 ) = sqrt301 ⇒d=√256+36+9=√301 ≈ 17.35 # (2 decimal places
