What is the distance between #(-15,36)# and # (–3, 2) #?

1 Answer
Jul 25, 2018

Answer:

The distance is #10sqrt13# or about #36.056# (rounded to nearest thousandth's place).

Explanation:

The formula for the distance of 2-dimensional coordinates is: #d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)#

We have the two coordinates, so we can plug in the values for #x# and #y#:
#d = sqrt((-3-(-15))^2 + (2-36)^2)#

Now we simplify:
#d = sqrt((12)^2 + (-34)^2)#

#d = sqrt(144 + 1156)#

#d = sqrt(1300)#

#d = 10sqrt13#

If you want to leave it in exact form, you can leave the distance as #10sqrt13#. However, if you want the decimal answer, here it is rounded to the nearest thousandth's place:
#d ~~ 36.056#

Hope this helps!