# What is the distance between (2, 0, –1)  and (–1, 4, –2) ?

Mar 31, 2018

Distance between $\left(2 , 0 , - 1\right) \mathmr{and} \left(- 1 , 4 , - 2\right)$ is $\sqrt{26}$ unit.

#### Explanation:

The distance between two points $P \left({x}_{1} , {y}_{1} , {z}_{1}\right)$ and

$Q \left({x}_{2} , {y}_{2} , {z}_{2}\right)$ in xyz-space is given by formula,

D=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2

Here $P = \left(2 , 0 , - 1\right) \mathmr{and} Q = \left(- 1 , 4 , - 2\right)$

D(P,Q)=sqrt((-1-2)^2+(4-0)^2+(-2+1)^2 or

$D \left(P , Q\right) = \sqrt{9 + 16 + 1} = \sqrt{26}$ unit

Distance between $\left(2 , 0 , - 1\right) \mathmr{and} \left(- 1 , 4 , - 2\right)$ is $\sqrt{26}$ unit

[Ans]