What is the distance between #(2, 0, –1) # and #(–1, 4, –2) #?

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Answer 1 · 2018-03-31T04:07:16

Distance between #(2,0,-1) and (-1,4,-2) # is # sqrt 26# unit.

The distance between two points #P(x_1,y_1,z_1)# and

#Q(x_2,y_2,z_2)# in xyz-space is given by formula,

#D=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2#

Here # P=(2,0,-1) and Q=(-1,4,-2) #

#D(P,Q)=sqrt((-1-2)^2+(4-0)^2+(-2+1)^2# or

#D(P,Q)=sqrt(9+16+1)= sqrt 26# unit

Distance between #(2,0,-1) and (-1,4,-2) # is # sqrt 26# unit

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