What is the distance between #(-2,1,-13)# and #(4,3,-12)#? Algebra Radicals and Geometry Connections Distance Formula 1 Answer ali ergin May 3, 2016 #s=sqrt41# Explanation: #A=(-2,1,-13)# #B=(4,3,-12)# #A_x=-2# #A_y=1# #A_z=-13# #B_x=4# #B_y=3# #B_z=-12# #"distance between A and B can be calculated by formula:"# #s=sqrt((B_x-A_x)^2+(B_y-A_y)^2+(B_z-A_z)^2)# #s=sqrt((4+2)^2+(3-1)^2+(-12+13)^2)# #s=sqrt(6^2+2^2+1^2)=sqrt(36+4+1)=sqrt(41)# Answer link Related questions What is the Distance Formula? How can the distance formula be derived from the pythagorean theorem? How can the distance formula be used in real life? How do you find the distance when given two coordinate points? How do you find the distance between (7, 7) and (–7, 7)? Does it matter which coordinate is #(x_1,y_1)# when applying the distance formula? How do you find all points that have an x -coordinate of –4 and whose distance from point (4, 2) is 10? How do you find the distance between (2.3, 4.5) and (–3.4, –5.2)? What is the distance between the origin of a Cartesian coordinate system and the point (5, -2)? How do you find the length of the line segment between the points (5,1) and (5,6)? See all questions in Distance Formula Impact of this question 1179 views around the world You can reuse this answer Creative Commons License