# What is the distance between (-2,1) and  (–4, 7) ?

Mar 11, 2016

$d = 2 \sqrt{10}$
$d = 6.32$

#### Explanation:

The distance formula is $d = \sqrt{{\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({x}_{2} - {x}_{1}\right)}^{2}}$

$\left(- 2 , 1\right) \mathmr{and} \left(- 4 , 7\right)$

${x}_{1} = - 2$
${y}_{1} = 1$
${x}_{2} = - 4$
${y}_{2} = 7$

$d = \sqrt{{\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({x}_{2} - {x}_{1}\right)}^{2}}$
$d = \sqrt{{\left(7 - 1\right)}^{2} + {\left(- 4 - \left(- 2\right)\right)}^{2}}$
$d = \sqrt{{\left(6\right)}^{2} + {\left(- 2\right)}^{2}}$
$d = \sqrt{36 + 4}$
$d = \sqrt{40}$
$d = 2 \sqrt{10}$
$d = 6.32$