What is the distance between (2, -3) and (5, -4)?

Oct 1, 2016

$\sqrt{58}$ units

Explanation:

We have: $\left(2 , - 3\right)$ and $\left(5 , - 4\right)$

Let's apply the distance formula:

$\implies d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}$

$\implies d = \sqrt{{\left(5 - 2\right)}^{2} + {\left(- 4 - \left(- 3\right)\right)}^{2}}$

$\implies d = \sqrt{{3}^{2} + {\left(- 7\right)}^{2}}$

$\implies d = \sqrt{9 + 49}$

$\implies d = \sqrt{58}$

Therefore, the distance between the two points $\left(2 , - 3\right)$ and $\left(5 , - 4\right)$ is $\sqrt{58}$ units.