What is the distance between #(2,-4)# and #(-1,-1)#?

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Answer 1 · 2018-04-16T04:24:17

The distance is #3sqrt2#.

The distance formula is:
#d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

Since we have the value of two points, we can plug them into the distance formula:

#d = sqrt((-1-2)^2 + (-1-(-4))^2)#

And now simplify:
#d = sqrt((-3)^2 + (-1+4)^2)#

#d = sqrt(9 + (3)^2)#

#d = sqrt(9 + 9)#

#d = sqrt(18)#

#d = sqrt(9 * 2)#

#d = sqrt9 * sqrt2#

#d = 3sqrt2#

The distance is #3sqrt2#.

Hope this helps!