What is the distance between  (-2, 4)  and (8, 8)?

2\sqrt{29}=10.77\ text{unit

Explanation:

The distance between the points $\left({x}_{1} , {y}_{1}\right) \setminus \equiv \left(- 2 , 4\right)$ & $\left({x}_{2} , {y}_{2}\right) \setminus \equiv \left(8 , 8\right)$ is given by using distance formula as follows

$\setminus \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}}$

$= \setminus \sqrt{{\left(- 2 - 8\right)}^{2} + {\left(4 - 8\right)}^{2}}$

$= 2 \setminus \sqrt{29}$

=10.77\ text{unit

Jul 24, 2018

$\sqrt{116} \approx 10.77 \text{ to 2 dec. places}$

Explanation:

$\text{Calculate the distance d using the "color(blue)"distance formula}$

•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)

$\text{let "(x_1,y_1)=(-2,4)" and } \left({x}_{2} , {y}_{2}\right) = \left(8 , 8\right)$

$d = \sqrt{{\left(8 - \left(- 2\right)\right)}^{2} + {\left(8 - 4\right)}^{2}}$

$\textcolor{w h i t e}{d} = \sqrt{100 + 16} = \sqrt{116} \approx 10.77$