What is the distance between #(2,6)# and #(4,4)#?

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Answer 1 · 2015-11-26T16:54:16

#2sqrt(2)#

Consider these point as forming a triangle. You can then use Pythagoras to solve the length of the hypotenuse (the line between the points.

Let the distance be d

Let #(x_1,y_1) -> (2,6)#
Let #(x_2,y_2)->(4,4)#

Then
#d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#d=sqrt((4-2)^2+(4-6)^2)#

#d=sqrt(2^2+(-2)^2)#

#d=sqrt(8) = sqrt(2xx2^2)#

#d=2sqrt(2)#

By keeping the square root you have an exact solution.
If you tried using decimal it would not be!