What is the distance between #(2,-6)# and #(4,-4)#?

1 Answer
Jan 19, 2016

Answer:

#2sqrt(2)# units

Explanation:

The distance formula for Cartesian coordinates is

#d=sqrt((x_2-x_1)^2+(y_2-y_1)^2#
Where #x_1, y_1#, and#x_2, y_2# are the Cartesian coordinates of two points respectively.
Let #(x_1,y_1)# represent #(2,-6)# and #(x_2,y_2)# represent #(4.-4)#.
#implies d=sqrt((4-2)^2+(-4-(-6))^2#
#implies d=sqrt((2)^2+(-4+6)^2#
#implies d=sqrt(4+(2)^2#
#implies d=sqrt(4+4#
#implies d=sqrt(8#
#implies d=2sqrt(2# units

Hence the distance between the given points is #2sqrt(2)# units.