# What is the distance between (2,-6) and (4,-4)?

Jan 19, 2016

$2 \sqrt{2}$ units

#### Explanation:

The distance formula for Cartesian coordinates is

d=sqrt((x_2-x_1)^2+(y_2-y_1)^2
Where ${x}_{1} , {y}_{1}$, and${x}_{2} , {y}_{2}$ are the Cartesian coordinates of two points respectively.
Let $\left({x}_{1} , {y}_{1}\right)$ represent $\left(2 , - 6\right)$ and $\left({x}_{2} , {y}_{2}\right)$ represent $\left(4. - 4\right)$.
implies d=sqrt((4-2)^2+(-4-(-6))^2
implies d=sqrt((2)^2+(-4+6)^2
implies d=sqrt(4+(2)^2
implies d=sqrt(4+4
implies d=sqrt(8
implies d=2sqrt(2 units

Hence the distance between the given points is $2 \sqrt{2}$ units.