What is the distance between #(3, –1, 1) # and # (1, –2, 0) #?

1 Answer
Apr 18, 2017

Answer:

#sqrt6~~2.45" to 2 dec. places"#

Explanation:

Use the 3-d version of the #color(blue)"distance formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2))color(white)(2/2)|)))#
where # (x_1,y_1,z_1),(x_2,y_2,z_2)" are 2 coordinate points"#

#"the 2 points here are " (3,-1,1)" and " (1,-2,0)#

#"let " (x_1,y_1,z_1)=(3,-1,1),(x_2,y_2,z_2)=(1,-2,0)#

#d=sqrt((1-3)^2+(-2+1)^2+(0-1)^2)#

#color(white)(d)=sqrt(4+1+1)#

#color(white)(d)=sqrt6~~2.45" to 2 dec. places"#