What is the distance between #(3, –1, 1) # and #(–2, 0, 1) #?

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Answer 1 · 2016-02-19T13:11:19

#sqrt26#

Pythagorean Theorem (3D version)

#sqrt{(3 - (-2))^2 + (-1 - 0)^2 + (1 - 1)^2} = sqrt26#

Answer 2 · 2016-02-19T13:12:41

#sqrt(26)~~5.099#

Using Pythagorean Theorem (in 3D)
#color(white)("XXX")d=sqrt((Delta x)^2+(Delta y)^2+(Delta Z)^2)#

#color(white)("XXXx")=sqrt((3-(-2))^2+(-1-0)^2+(1-1)^2))#

#color(white)("XXXx")=sqrt(25+1+0) = sqrt(26) ~~5.099#