# What is the distance between (3, –1, 1)  and (–2, 0, 1) ?

Feb 19, 2016

$\sqrt{26}$

#### Explanation:

Pythagorean Theorem (3D version)

$\sqrt{{\left(3 - \left(- 2\right)\right)}^{2} + {\left(- 1 - 0\right)}^{2} + {\left(1 - 1\right)}^{2}} = \sqrt{26}$

Feb 19, 2016

$\sqrt{26} \approx 5.099$
$\textcolor{w h i t e}{\text{XXX}} d = \sqrt{{\left(\Delta x\right)}^{2} + {\left(\Delta y\right)}^{2} + {\left(\Delta Z\right)}^{2}}$
color(white)("XXXx")=sqrt((3-(-2))^2+(-1-0)^2+(1-1)^2))
$\textcolor{w h i t e}{\text{XXXx}} = \sqrt{25 + 1 + 0} = \sqrt{26} \approx 5.099$