Question

What is the distance between `(3, –1, 1)` and #(3, 2, 1) #?

Answer 1

Distance = 3 units

Explanation:

The distance D = `sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)`
So D = `sqrt((3-3)^2+(2+1)^2+(1-1)^2) or D = sqrt 9 or D=3 [Ans]`