What is the distance between (–3,1) and (2,4) on the coordinate plane?

Apr 8, 2017

See explanation.

Explanation:

If 2 points are given:

and

$B = \left({x}_{B} , {y}_{B}\right)$ 

then to calculate the distance between the points you use the formula:

$| A B | = \sqrt{{\left({x}_{B} - {x}_{A}\right)}^{2} + {\left({y}_{B} - {y}_{A}\right)}^{2}}$

In the example we have:

$| A B | = \sqrt{{\left(2 - \left(- 3\right)\right)}^{2} + {\left(4 - 1\right)}^{2}} = \sqrt{{5}^{2} + {3}^{2}} = \sqrt{34}$

Answer: The distance between the points is $\sqrt{34}$