What is the distance between #(-3 , (13 pi)/12 )# and #(-1 , pi/4 )#?

1 Answer
Jack H.
Oct 9, 2017

#sqrt(4 + (25 π^2)/36)#

Explanation:

When you want to know distance between A and B when #A(x_1, y_1)#, #B(x_2, y_2)#, According to Pythagoras' Theorem, You get the distance as

Line #AB=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

So for your question, #x_1=-3, y_1=(13pi)/12, x_2=-1, y_2=pi/4#

Plug in those four values into #sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#sqrt((-1-(-3))^2+(pi/4-(13pi)/12)^2)#

#=sqrt(4 + 25/36pi^2)#

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