Question

What is the distance between `(3, 2, 1)` and #(–1, 4, –2) #?

Answer 1

`sqrt29`

Explanation:

The distance between 2 points `(x1,y1,z1) and (x2,y2,z2)`=`sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)`

So, the distance between `(3,2,1) and (-1,4,-2)`=`sqrt((-1-3)^2+(4-2)^2+(-2-1)^2)`
=`sqrt29`