What is the distance between #(3,2,-1)# and #(5,-1,6)#?
1 Answer
May 1, 2016
Explanation:
The distance
#d = sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#
#=sqrt((5-3)^2+(-1-2)^2+(6-(-1))^2)#
#=sqrt(2^2+(-3)^2+7^2)#
#=sqrt(4+9+49)#
#=sqrt(62) ~~ 7.874#
