# What is the distance between (3,6,-2) and (-3,-3,-1)?

Dec 1, 2015

distance $= 6 \sqrt{3}$
Given $\left(x , y , z\right)$ coordinate points $\left(3 , 6 , - 2\right)$ and $\left(- 3 , - 3 , - 1\right)$
$\left(\delta x , \delta y , \delta z\right) = \left(6 , 9 , 1\right)$
$= \sqrt{{6}^{2} + {9}^{2} + {1}^{1}} = \sqrt{36 + 81 + 1} = \sqrt{118} = 6 \sqrt{3}$