# What is the distance between (4, 3, 1) and (0, 6, 0) ?

Apr 27, 2018

$\sqrt{26} \approx 5.1 \text{ to 1 dec. place}$

#### Explanation:

$\text{use the 3-dimensional version of the "color(blue)"distance formula}$

•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)

$\text{let "(x_1,y_1,z_1)=(4,3,1)" and }$

$\left({x}_{2} , {y}_{2} , {z}_{2}\right) = \left(0 , 6 , 0\right)$

$d = \sqrt{{\left(0 - 4\right)}^{2} + {\left(6 - 3\right)}^{2} + {\left(0 - 1\right)}^{2}}$

$\textcolor{w h i t e}{d} = \sqrt{16 + 9 + 1} = \sqrt{26} \approx 5.1$