What is the distance between (4 ,( 7 pi)/8 ) and (-1 ,( 3pi )/2 )?

1 Answer
Jul 12, 2016

The distance is (5sqrt(16 + pi^2))/4

Explanation:

Distance between two points is the length of the vector between them. That is, for two points vecA and vecB, the distance will be: ||vecA - vecB||.

This means that for your points:
d = sqrt((4+1)^2 + ((7pi)/8 - (3pi)/2)^2)
= sqrt(5^2 + ((-5pi)/8)^2)
= sqrt(25 + (25pi^2)/16) = sqrt((400 + 25pi^2)/16)
= sqrt(400 + 25pi^2)/4 = (5sqrt(16 + pi^2))/4