What is the distance between $(–5, –1, 1)$ and $(4, –4, –2)$ ?

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Answer 1 · 2016-06-14T18:52:28

Distance = $sqrt99$ = $~=9.95.$

WE use the Distance Formula : The distance $d$ between two points $(a,b,c)$ and $(p,q.r)$ is $d=sqrt{(a-p)^2+(b-q)^2+(c-r)^2}.$

In our case, $d=sqrt{(-5-4)^2+(-1+4)^2+(1+2)^2}=sqrt(81+9+9)=sqrt99~=9.95.$

What is the distance between (–5, –1, 1) (–5, –1, 1) and (4, –4, –2)(4, –4, –2)?