# What is the distance between (5,-11,-5) and (4,-13,6)?

Let $A \left(5 , - 11 , - 5\right)$ and $B \left(4 , - 13 , 6\right)$. We can now create the vector $A B \left(- 1 , - 2 , 11\right)$. The distance between $A$ and $B$ is just the norm of the vector $A B$, which is $\sqrt{{\left(- 1\right)}^{2} + {\left(- 2\right)}^{2} + {11}^{2}} = \sqrt{126}$