# What is the distance between (5, –6, 4)  and (4, –4, –2)?

Distance $= \sqrt{41}$ units
Distance $= \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}} = \sqrt{{\left(4 - 5\right)}^{2} + {\left(- 4 + 6\right)}^{2} + {\left(- 2 - 4\right)}^{2}} = \sqrt{1 + 4 + 36} = \sqrt{41}$ [Ans]