What is the distance between #(5, –6, 4) # and #(–6, 3, 4)#?

1 Answer
Dec 6, 2015

Answer:

#sqrt(202)#

Explanation:

The distance between two points (in any dimension greater than or equal to #2#), is given by the square root of the sum of the squares of the differences of the correspondant coordinates. It's easier to write it in formulas than in words: if the two points are #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)#, then the distance is

#sqrt( (x_1-x_2)^2 +(y_1-y_2)^2 +(z_1-z_2)^2 ) #

So, in your case,

#sqrt( (5+6)^2 + (-6-3)^2 + (4-4)^2 ) =sqrt(11^2+(--)^2)#
#=sqrt(121+81)=sqrt(202)#