# What is the distance between (6,-2,4) and (8,4,0)?

Distance is $2 \sqrt{14}$ unit
Distance = $\sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$ So distance = $\sqrt{{\left(8 - 6\right)}^{2} + {\left(4 + 2\right)}^{2} + {\left(0 - 4\right)}^{2}}$ = $\sqrt{4 + 36 + 16} = \sqrt{56}$ =$2 \sqrt{14}$ [answer]