# What is the distance between (6,2,4) and (8,4,6)?

The distance is $3.46 \left(2 \mathrm{dp}\right) u n i t$
The distance is $d = \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2} + {\left({z}_{1} - {z}_{2}\right)}^{2}} = \sqrt{{\left(6 - 8\right)}^{2} + {\left(2 - 4\right)}^{2} + {\left(4 - 6\right)}^{2}} = \sqrt{4 + 4 + 4} = \sqrt{12} = 3.46 \left(2 \mathrm{dp}\right) u n i t$[Ans]