What is the distance between (7, 4) and (10, 8) ?

Mar 11, 2018

$d = 5$ units

Explanation:

Distance =sqrt((x_2-x_1)^2 + (y_2-y_1)^2
Here, ${x}_{2}$ is 10,
${x}_{1}$ is 7,
${y}_{2}$ is 8,
${y}_{1}$ is 4.

Substituting and solving we get:
d = sqrt((10-7)^2 + (8-4)^2
$d = \sqrt{{3}^{2} + {4}^{2}}$
$d = \sqrt{9 + 16}$
$d = \sqrt{25}$
$d = 5$ units